Musterlösung für Übungsaufgabe 2 vom 19.11.2015

20151126/aufgabe-2.c

+#include <stdio.h>
+
+#define ORIGINYEAR 1980
+
+int IsLeapYear (int year)
+{
+  if (year % 4)
+    return 0;
+  else if (year % 100)
+    return 1;
+  else if (year % 400)
+    return 0;
+  else
+    return 1;
+}
+
+int main (void)
+{
+  int days = (2008 - ORIGINYEAR) * 365 + 8 + 365;  /* 2008-12-31 */
+
+  int year = ORIGINYEAR;
+
+  while (days > 365)
+    {
+      if (IsLeapYear (year))
+        {
+          if (days > 366)
+            {
+              days -= 366;
+              year += 1;
+            }
+        }
+      else
+        {
+          days -= 365;
+          year += 1;
+        }
+    }
+
+  printf ("day #%d in the year %d\n", days, year);
+  return 0;
+}

20151126/loesung-2-0.c

+#include <stdio.h>
+
+#define ORIGINYEAR 1980
+
+int IsLeapYear (int year)
+{
+  if (year % 4)
+    return 0;
+  else if (year % 100)
+    return 1;
+  else if (year % 400)
+    return 0;
+  else
+    return 1;
+}
+
+int main (void)
+{
+  int days = (2008 - ORIGINYEAR) * 365 + 8 + 365;  /* 2008-12-31 */
+
+  int year = ORIGINYEAR;
+
+  while (days > 365)
+    {
+      if (IsLeapYear (year))
+        {
+          if (days > 366)
+            {
+              days -= 366;
+              year += 1;
+            }
+          else
+            break;
+        }
+      else
+        {
+          days -= 365;
+          year += 1;
+        }
+    }
+
+  printf ("day #%d in the year %d\n", days, year);
+  return 0;
+}

20151126/loesung-2-1.c

+#include <stdio.h>
+
+#define ORIGINYEAR 1980
+
+int IsLeapYear (int year)
+{
+  if (year % 4)
+    return 0;
+  else if (year % 100)
+    return 1;
+  else if (year % 400)
+    return 0;
+  else
+    return 1;
+}
+
+int DaysInYear (int year)
+{
+  if (IsLeapYear (year))
+    return 366;
+  else
+    return 365;
+}
+
+int main (void)
+{
+  int days = (2008 - ORIGINYEAR) * 365 + 8 + 365;  /* 2008-12-31 */
+
+  int year = ORIGINYEAR;
+
+  while (days > DaysInYear (year))
+    {
+      days -= DaysInYear (year);
+      year += 1;
+    }
+
+  printf ("day #%d in the year %d\n", days, year);
+  return 0;
+}

20151126/loesung-2-2.c

+#include <stdio.h>
+
+#define ORIGINYEAR 1980
+
+int IsLeapYear (int year)
+{
+  if (year % 4)
+    return 0;
+  else if (year % 100)
+    return 1;
+  else if (year % 400)
+    return 0;
+  else
+    return 1;
+}
+
+int DaysInYear (int year)
+{
+  if (IsLeapYear (year))
+    return 366;
+  else
+    return 365;
+}
+
+int main (void)
+{
+  int days = (2008 - ORIGINYEAR) * 365 + 8 + 365;  /* 2008-12-31 */
+
+  int year = ORIGINYEAR;
+  int days_in_year;
+
+  days_in_year = DaysInYear (year);
+  while (days > days_in_year)
+    {
+      days -= days_in_year;
+      year += 1;
+      days_in_year = DaysInYear (year);
+    }
+
+  printf ("day #%d in the year %d\n", days, year);
+  return 0;
+}

20151126/loesung-2-3.c

+#include <stdio.h>
+
+#define ORIGINYEAR 1980
+
+int IsLeapYear (int year)
+{
+  if (year % 4)
+    return 0;
+  else if (year % 100)
+    return 1;
+  else if (year % 400)
+    return 0;
+  else
+    return 1;
+}
+
+int DaysInYear (int year)
+{
+  if (IsLeapYear (year))
+    return 366;
+  else
+    return 365;
+}
+
+int main (void)
+{
+  int days = (2008 - ORIGINYEAR) * 365 + 8 + 365;  /* 2008-12-31 */
+
+  int year = ORIGINYEAR;
+  int days_in_year;
+
+  while (days > (days_in_year = DaysInYear (year)))
+    {
+      days -= days_in_year;
+      year += 1;
+    }
+
+  printf ("day #%d in the year %d\n", days, year);
+  return 0;
+}