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Commit 2bc1da3b authored by Peter Gerwinski's avatar Peter Gerwinski
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Mahtematik-Aufgaben mit LaTeX, 6.7.2021

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\documentclass{article}
\usepackage{enumerate}
\begin{document}
\begin{tabbing}
1) 1384 : 1000 = \textbf{1}\\
2) \=(1384 - 1 * 1000 = 384)\\
\> 384 : 100 = \textbf{3}\\
3) (1384 - 1 * 1000 - 3 * 100 = 84)\\
\> 84 : 10 = \textbf{8}\\
4) 1384 - 1 * 1000 - 3 * 100 - 8 * 10 = \textbf{4}
\end{tabbing}
\begin{enumerate}
\item
1384 : 1000 = \textbf{1}
\item
(1384 - 1 * 1000 = 384)\\
384 : 100 = \textbf{3}
\item
(1384 - 1 * 1000 - 3 * 100 = 84)\\
84 : 10 = \textbf{8}
\item
1384 - 1 * 1000 - 3 * 100 - 8 * 10 = \textbf{4}
\end{enumerate}
\begin{enumerate}[1)]
\item
1384 : 1000 = \textbf{1}
\item
(1384 - 1 * 1000 = 384)\\
384 : 100 = \textbf{3}
\item
(1384 - 1 * 1000 - 3 * 100 = 84)\\
84 : 10 = \textbf{8}
\item
1384 - 1 * 1000 - 3 * 100 - 8 * 10 = \textbf{4}
\end{enumerate}
\begin{enumerate}[1)]
\item
$1384 : 1000 = \textbf{1}$
\item
$(1384 - 1 \cdot 1000 = 384)$\\
$384 : 100 = \textbf{3}$
\item
$(1384 - 1 \cdot 1000 - 3 \cdot 100 = 84)$\\
$84 : 10 = \textbf{8}$
\item
$1384 - 1 \cdot 1000 - 3 \cdot 100 - 8 \cdot 10 = \textbf{4}$
\end{enumerate}
\end{document}
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