Vorbereitung 26.11.2018

20181119/hp-20181119.tex

@@ -20,7 +20,7 @@
 % Attribution-ShareAlike 3.0 Unported License along with this
 % document.  If not, see <http://creativecommons.org/licenses/>.
 
-% README: Vertiefung: Bibliotheken, Differentialgleichungen
+% README: Präprozessor-Makros, Bibliothek verwenden (Beispiel: GTK+), Differentialgleichungen
 
 \documentclass[10pt,t]{beamer}
 
@@ -69,13 +69,13 @@
         \item[3.2] Bibliotheken einbinden
         \color{orange}
         \item[3.3] Bibliotheken verwenden
-        \color{red}
+        \color{black}
         \item[3.4] Projekt organisieren: make
       \end{itemize}
     \item[\textbf{4}] \textbf{Hardwarenahe Programmierung}
     \item[\textbf{5}] \textbf{Algorithmen}
       \begin{itemize}
-        \color{medgreen}
+        \color{orange}
         \item[5.1] Differentialgleichungen
         \color{black}
         \vspace*{-0.1cm}
@@ -205,20 +205,19 @@
       Compiler-Aufruf:
       \begin{onlyenv}<4>
         \begin{lstlisting}[style=terminal,gobble=10]
-          $ ¡gcc -Wall -O hello-gtk.c -pthread -I/usr/include/gtk
-          -3.0 -I/usr/include/at-spi2- atk/2.0 -I/usr/include/at-
-          spi-2.0 -I/usr/include/dbus-1 .0 -I/usr/lib/x86_64-linu
-          x-gnu/dbus-1.0/include -I/usr/ include/gtk-3.0 -I/usr/i
-          nclude/gio-unix-2.0/ -I/usr/inc lude/cairo -I/usr/inclu
-          de/pango-1.0 -I/usr/include/harf buzz -I/usr/include/pa
-          ngo-1.0 -I/usr/include/atk-1.0 -I /usr/include/cairo -I
-          /usr/include/pixman-1 -I/usr/inclu de/freetype2 -I/usr/
-          include/libpng16 -I/usr/include/gdk -pixbuf-2.0 -I/usr/
-          include/libpng16 -I/usr/include/glib -2.0 -I/usr/lib/x8
-          6_64-linux-gnu/glib-2.0/include -lgtk -3 -lgdk-3 -lpang
-          ocairo-1.0 -lpango-1.0 -latk-1.0 -lcai ro-gobject -lcai
-          ro -lgdk_pixbuf-2.0 -lgio-2.0 -lgobject -2.0 -lglib-2.0
-          -o hello-gtk¿
+          $ ¡gcc -Wall -O hello-gtk.c -pthread -I/usr/include/gtk-
+          3.0 -I/usr/include/at-spi2-atk/2.0 -I/usr/include/at-sp
+          i-2.0 -I/usr/include/dbus-1.0 -I/usr/lib/x86_64-linux-g
+          nu/dbus-1.0/include -I/usr/include/gtk-3.0 -I/usr/inclu
+          de/gio-unix-2.0/ -I/usr/include/cairo -I/usr/include/pa
+          ngo-1.0 -I/usr/include/harfbuzz -I/usr/include/pango-1.
+          0 -I/usr/include/atk-1.0 -I/usr/include/cairo -I/usr/in
+          clude/pixman-1 -I/usr/include/freetype2 -I/usr/include/
+          libpng16 -I/usr/include/gdk-pixbuf-2.0 -I/usr/include/l
+          ibpng16 -I/usr/include/glib-2.0 -I/usr/lib/x86_64-linux
+          -gnu/glib-2.0/include -lgtk-3 -lgdk-3 -lpangocairo-1.0
+          -lpango-1.0 -latk-1.0 -lcairo-gobject -lcairo -lgdk_pix
+          buf-2.0 -lgio-2.0 -lgobject-2.0 -lglib-2.0-o hello-gtk¿
         \end{lstlisting}
         \vspace*{-1cm}
       \end{onlyenv}
@@ -466,6 +465,8 @@
 
 \end{frame}
 
+\iffalse
+
 \setcounter{section}{2}
 \section{Bibliotheken}
 \setcounter{subsection}{3}
@@ -541,6 +542,8 @@
 
 \end{frame}
 
+\fi
+
 \nosectionnonumber{\inserttitle}
 
 \begin{frame}
@@ -557,6 +560,7 @@
         \item[3.1] Der Präprozessor
         \item[3.2] Bibliotheken einbinden
         \item[3.3] Bibliotheken verwenden
+        \color{red}
         \item[3.4] Projekt organisieren: make
       \end{itemize}
     \item[\textbf{4}] \textbf{Hardwarenahe Programmierung}

20181126/Makefile-1

+philosophy: philosophy.o answer.o
+	gcc philosophy.o answer.o -o philosophy
+
+answer.o: answer.c answer.h
+	gcc -Wall -O answer.c -c
+
+philosophy.o: philosophy.c answer.h
+	gcc -Wall -O philosophy.c -c

20181126/Makefile-2

+TARGET = philosophy
+OBJECTS = philosophy.o answer.o
+HEADERS = answer.h
+CFLAGS = -Wall -O
+
+$(TARGET): $(OBJECTS)
+	gcc $(OBJECTS) -o philosophy
+
+answer.o: answer.c $(HEADERS)
+	gcc $(CFLAGS) answer.c -c
+
+philosophy.o: philosophy.c $(HEADERS)
+	gcc $(CFLAGS) philosophy.c -c
+
+clean:
+	rm -f $(OBJECTS) $(TARGET)

20181126/Makefile-3

+TARGET = philosophy
+OBJECTS = philosophy.o answer.o
+HEADERS = answer.h
+CFLAGS = -Wall -O
+
+$(TARGET): $(OBJECTS)
+	gcc $(OBJECTS) -o philosophy
+
+%.o: %.c $(HEADERS)
+	gcc $(CFLAGS) $< -c
+
+clean:
+	rm -f $(OBJECTS) $(TARGET)

20181126/answer.c

+#include "answer.h"
+
+int answer (void)
+{
+  return 23;
+}

20181126/answer.h

+extern int answer (void);

20181126/aufgabe-2.c

+#include <avr/io.h>
+
+int main (void)
+{
+  DDRA = 0xff;
+  DDRB = 0xff;
+  DDRC = 0xff;
+  DDRD = 0xff;
+  PORTA = 0x1f;
+  PORTB = 0x10;
+  PORTD = 0x10;
+  PORTC = 0xfc;
+  while (1);
+  return 0;
+}

20181126/hp-uebung-20181126.tex

+% hp-uebung-20181119.pdf - Exercises on Low-Level Programming / Applied Computer Sciences
+% Copyright (C) 2013, 2015, 2016, 2017, 2018  Peter Gerwinski
+%
+% This document is free software: you can redistribute it and/or
+% modify it either under the terms of the Creative Commons
+% Attribution-ShareAlike 3.0 License, or under the terms of the
+% GNU General Public License as published by the Free Software
+% Foundation, either version 3 of the License, or (at your option)
+% any later version.
+%
+% This document is distributed in the hope that it will be useful,
+% but WITHOUT ANY WARRANTY; without even the implied warranty of
+% MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+% GNU General Public License for more details.
+%
+% You should have received a copy of the GNU General Public License
+% along with this document.  If not, see <http://www.gnu.org/licenses/>.
+%
+% You should have received a copy of the Creative Commons
+% Attribution-ShareAlike 3.0 Unported License along with this
+% document.  If not, see <http://creativecommons.org/licenses/>.
+
+% README: Zahlensysteme, Mikro-Controller
+
+\documentclass[a4paper]{article}
+
+\usepackage{pgscript}
+
+\begin{document}
+
+  \thispagestyle{empty}
+
+  \section*{Hardwarenahe Programmierung\\
+            Übungsaufgaben -- 26.\ November 2018}
+
+  Diese Übung enthält Punkteangaben wie in einer Klausur.
+  Um zu "`bestehen"', müssen Sie innerhalb von 70 Minuten
+  unter Verwendung ausschließlich zugelassener Hilfsmittel
+  14 Punkte (von insgesamt \totalpoints) erreichen.
+
+  \exercise{Zahlensysteme}
+
+  Wandeln Sie ohne Hilfsmittel
+
+  \begin{minipage}[t]{0.3\textwidth}
+    \begin{itemize}
+      \item
+        nach Dezimal:
+        \begin{itemize}
+          \item[(a)]
+            0010\,0000$_2$
+          \item[(b)]
+            42$_{16}$
+          \item[(c)]
+            17$_8$
+        \end{itemize}
+    \end{itemize}
+  \end{minipage}\hfill
+  \begin{minipage}[t]{0.3\textwidth}
+    \begin{itemize}
+      \item
+        nach Hexadezimal:
+        \begin{itemize}
+          \item[(d)]
+            0010\,0000$_2$
+          \item[(e)]
+            42$_{10}$
+          \item[(f)]
+            192.168.20.254$_{256}$
+        \end{itemize}
+    \end{itemize}
+  \end{minipage}\hfill
+  \begin{minipage}[t]{0.3\textwidth}
+    \begin{itemize}
+      \item
+        nach Binär:
+        \begin{itemize}
+          \item[(g)]
+            750$_8$
+          \item[(h)]
+            42$_{10}$
+          \item[(i)]
+            AFFE$_{16}$
+        \end{itemize}
+    \end{itemize}
+  \end{minipage}
+  
+  \medskip
+
+  Berechnen Sie ohne Hilfsmittel:
+  \begin{itemize}
+    \item[(j)]
+      750$_8$ \& 666$_8$
+    \item[(k)]
+      A380$_{16}$ + B747$_{16}$
+    \item[(l)]
+      AFFE$_{16} >> 1$
+  \end{itemize}
+
+  Die tiefgestellte Zahl steht für die Basis des Zahlensystems.
+  Jede Teilaufgabe zählt 1 Punkt. \addtocounter{points}{12}
+
+  (In der Klausur sind Hilfsmittel zugelassen,
+  daher ist dies \emph{keine\/} typische Klausuraufgabe.)
+
+  \exercise{Mikro-Controller}
+
+  \begin{minipage}[t]{10cm}
+    An die vier Ports eines ATmega16-Mikro-Controllers sind Leuchtdioden angeschlossen:
+    \begin{itemize}
+      \item
+        von links nach rechts an die Ports A, B, C und D,
+      \item
+        von oben nach unten an die Bits Nr.\ 0 bis 7.
+    \end{itemize}
+
+    Wir betrachten das folgende Programm (\gitfile{hp}{20181126}{aufgabe-2.c}):
+
+    \begin{lstlisting}[gobble=6]
+      #include <avr/io.h>
+
+      int main (void)
+      {
+        DDRA = 0xff;
+        DDRB = 0xff;
+        DDRC = 0xff;
+        DDRD = 0xff;
+        PORTA = 0x1f;
+        PORTB = 0x10;
+        PORTD = 0x10;
+        PORTC = 0xfc;
+        while (1);
+        return 0;
+      }
+    \end{lstlisting}
+  \end{minipage}\hfill
+  \begin{minipage}[t]{3cm}
+    \strut\\[-\baselineskip]
+    \includegraphics[width=3cm]{leds.jpg}
+  \end{minipage}
+
+  \vspace*{-3cm}
+
+  \strut\hfill
+  \begin{minipage}{11.8cm}
+    \begin{itemize}
+      \item[(a)]
+        Was bewirkt dieses Programm? \points{4}
+      \item[(b)]
+        Wozu dienen die ersten vier Zeilen des Hauptprogramms? \points{2}
+      \item[(c)]
+        Was würde stattdessen die Zeile \lstinline{DDRA, DDRB, DDRC, DDRD = 0xff;} bewirken?
+        \points{2}
+      \item[(d)]
+        Schreiben Sie das Programm so um,
+        daß die durch das Programm dargestellte Figur spiegelverkehrt erscheint. \points{3}
+      \item[(e)]
+        Wozu dient das \lstinline{while (1)}? \points{2}
+      \item
+        Alle Antworten bitte mit Begründung.
+    \end{itemize}
+  \end{minipage}
+
+  \begin{flushright}
+    \textit{Viel Erfolg!}
+  \end{flushright}
+
+  \makeatletter
+    \immediate\write\@mainaux{\string\gdef\string\totalpoints{\arabic{points}}}
+  \makeatother
+
+\end{document}

20181126/io-ports-and-interrupts.pdf

+../common/io-ports-and-interrupts.pdf
\ No newline at end of file

20181126/leds.jpg

+../common/leds.jpg
\ No newline at end of file

20181126/logo-hochschule-bochum-cvh-text-v2.pdf

+../common/logo-hochschule-bochum-cvh-text-v2.pdf
\ No newline at end of file

20181126/logo-hochschule-bochum.pdf

+../common/logo-hochschule-bochum.pdf
\ No newline at end of file

20181126/pendulum.pdf

+../common/pendulum.pdf
\ No newline at end of file

20181126/pgscript.sty

+../common/pgscript.sty
\ No newline at end of file

20181126/pgslides.sty

+../common/pgslides.sty
\ No newline at end of file

20181126/philosophy.c

+#include <stdio.h>
+#include "answer.h"
+
+int main (void)
+{
+  printf ("The answer is %d.\n", answer ());
+  return 0;
+}